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324x^2+72x+2=0
a = 324; b = 72; c = +2;
Δ = b2-4ac
Δ = 722-4·324·2
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-36\sqrt{2}}{2*324}=\frac{-72-36\sqrt{2}}{648} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+36\sqrt{2}}{2*324}=\frac{-72+36\sqrt{2}}{648} $
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